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    Need solutions to a math problem

    Hi guys,

    I have a mathematical problem I need help in solving:

    I have a given length of material that measures 2,000mm. I have to cut this length into various pieces.

    Measurements of each piece:
    A = 280mm
    B = 270mm
    C = 260mm

    If I require two times more pieces of C than A and B, what would be the optimum combination of A, B and C I may cut from the 2,000mm that results in the least amount of wastage?

    Is there some mathematic algorithm for this?

    Thanks in advance
    Irony = displaying enough parking coupons on your dashboard but getting fined for littering when you throw the stubs on the floor

    #2
    The parameters given don't allow much wiggle room.

    Total cannot exceed 2000mm, and A, B and C are each quite large in comparison, in addition to the fact that there must be "two times more pieces of C than A and B".

    Then there can be only 3 combinations of A, B and C that don't exceed 2000mm in total.

    A = 0 pieces, B = 2 pieces, C = 4 pieces
    A = 1 piece, B = 1 piece, C = 4 pieces
    A = 2 pieces, B = 0 piece, C = 4 pieces

    The last option gives the least wastage, i.e. 400mm remaining. Is this what's being asked, or I interpret the question wrongly??
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